S = 1 + 1/2 + 1/3 +.....+ 1/ N

Calculate The Value Of This Sum Series [ S = 1 + 1/2 + 1/3 +...+ 1/N ] 

Source code :-

#include<stdio.h>

int main()

{

    int n;

    float i=1.0,s=0.0;

    printf("Enter the value of n: ");

    scanf("%d",&n);

    while(i<=n)

    {

        s=s+(i/(i+1));

        i=i+1;

    }

    printf("Sum is => %.2f",s);

    return 1;

}

Input-Output :-

abhi@hp-15q-laptop:~$ gcc s.c

abhi@hp-15q-laptop:~$ ./a.out

Enter the value of n: 5

Sum is => 3.55